An exercise I use as the start of a math masterclass is to calculate the distance to the moon using a pendulum and a calendar. The answer is remarkably close to the one obtained by these kids using recordings from the Apollo missions.
If NASA really did fake the Moon landings, they did a bloody good job!
If you want to know how to calculate the distance, let me know and I'll write something about it.
Suppose the moon is in a circular orbit with radius R and angular velocity w. Then its position looks like R exp(iwt), so its acceleration is the second derivative of this = -Rw^2 exp(iwt), whose magnitude is -Rw^2. (That's a standard formula but I always have to derive it from scratch.) So GM = R^3w^2.
Now, what do we know? If we have a calendar that marks full moons, we know how often the occur and therefore we know w. What about the stuff involving GM? Well, now construct a pendulum. Standard formulae again but let's do it from scratch again. Length L, angular displacement a: vertical displacement is negligible to first order, so for small displacements the restoring force just comes from the tension in the string. To first order again, that equals the gravitational force on the mass, so the horizontal component of the acceleration is GM/r^2.La where r is the radius of the earth. So, measure the period of the pendulum (and of course its length); that tells us a and therefore GM/r^2. So provided we know r we now have GM and therefore R, and we're done.
So, one remaining question for RiderOfGiraffes: are you happy to look up r in a reference book for this exercise, or do you have a classroom-friendly way of getting that by simple observation and calculation too?
You mean apart from the original definition of the meter as one ten millionth of the distance from the north pole to the equator passing through Paris? That means the circumference of the Earth is 40*10^6 meters, so the radis is that over 2pi.
I guess, then, in addition to the pendulum, stopwatch and calendar we also need a ruler. We can use these to measure the size of the Earth directly using either the method of Eratosthenes (who also created the sieve for finding primes, and invented the system of latitude and longitude) or using the method used by Abu al-Rayhan al-Biruni.
That last, by the way, is cool, and I intend to use it in my next maths masterclass field trip.
Yes, I do mean other than apart from the original definition which, after all, is not the current definition. (You could say "but everyone knows ...", but then you could equally say that "everyone knows" g ~= 9.8m/s^2.) The Eratosthenes method is lovely but surely rather difficult in a classroom. (Am I missing a trick?) All I know about the al-Biruni method is a couple of sentences from Wikipedia, but it sounds as if it effectively needs some external (geographical) data that you can't measure in a classroom. Hmm.
l L^2 R^2 = P^2 D^3
l = pendulum length (assume 1m)
P = pendulum period (roughly 2s)
L = Lunar orbital time (27.32 * 86400)
R = Radius of the Earth
D = Distance to the Moon
Now we also know that in a total Lunar eclipse the Moon moves through the Earth's shadow. Assume it moves directly through the center. Measure the time for the Moon to move from touching the umbra to completely exiting the umbra. The distance it moves is then pretty much one Earth diameter, because the apparent sizes of the Sun and Moon are the same.
So R/D = (T/2)(2pi/L) where T is the transit time, and turns out from observations to be around 12500 seconds.
For really accurate measurements check out http://www.physics.ucsd.edu/~tmurphy/apollo/apollo.html
By bouncing a laser off several reflectors that were left on the moon, they are able to get accuracies of one millimeter.
If NASA really did fake the Moon landings, they did a bloody good job!
If you want to know how to calculate the distance, let me know and I'll write something about it.